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| Theorem 1 | ||||
| If x is any real number and t is any integer then | ||||
x + t
=
x
+ t
|
||||
| proof of Theorem 1 | |
Theorem 1 is obviously true if x and t are both integers.
So, let's assume that x is not an integer.
Then x must lie between two consecutive integers, say
k and k+1 :
k < x < k+1
Obviously k =
x
.
Adding t throughout the above inequality we get
k + t < x + t < k+ t + 1
Note that x + t lies between the consecutive integers k+t and k+t+1
Therefore,
x + t
= k + t =
x
+ t
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