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| Theorem 5 | ||||
|
If x is any real number then -
-x
is the smallest integer greater than or
equal to x
|
||||
| proof of Theorem 5 | |
Theorem 5 is obviously true if x is an integer.
So, let's assume that x is not an integer.
Then there must exist a real number
α such that
x =
x
+ α
and
0 < α < 1.
Then -x =
-
x
+ ( -α )
where
-1 < -α < 0.
Now use the trick of adding and subtracting the same
value to some item.
Here we subtract and
add 1 to the right hand side of the above equation.
-x =
-1 -
x
+
( 1 - α )
where
0 < 1 - α < 1
| By theorem 1, |
-x
|
= |
-1 -
x
+
1 - α
|
statement 1 | |
| = |
-1 -
x
|
statement 2 | |||
| Therefore, |
-
-x
|
= |
1 +
x
|
statement 3 | |
| x not an integer | → | x must lie between two consecutive integers | |||
| → |
x
<
x
<
1 +
x
|
||||
Since
1 +
x
is obviously the smallest integer greater
than x,
|
|||||
and since, by statement 3,
1 +
x
=
-
-x
,
we are done with this case. |
|||||
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