In a craps game what are the odds against rolling a 9 before a 7 ?
Let p = probability of rolling 9 before 7.
From example 12, p = 2 / 5.
Using 1/p = 1 + g → 5 / 2 = 1 + g → g = 3 / 2
Thus, for a pass line bettor whose point is 9, the odds against winning are three to two.